If the zeroes of the quadratic polynomial x 2  + (a + 1)x + b are 2 and –3, then (A) a = –7, b = –1    (B) a = 5, b = –1 (C) a = 2, b = –6     (D) a = 0, b = – 6

Respuesta :

Answer:

(D) a = 0, b = – 6

Step-by-step explanation:

x²  + (a + 1)x + b = (x - 2) ( x + 3)

= x² + x - 6

a + 1 = 1

a = 0

b = -6