kens1ang kens1ang
  • 17-04-2020
  • Mathematics
contestada

Help me prove that sec(a-b) =seca*secb/1+tana*tanb​

Respuesta :

Lightx
Lightx Lightx
  • 17-04-2020

Use:

[tex] sec a=\frac{1}{cos a}[/tex]

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PollyP52 PollyP52
  • 17-04-2020

Answer:

See below.

Step-by-step explanation:

Write the sec's as 1 / cos  and the tan's as sin / cos

I will write sin as s and cos as c:

Left side  =  1 / ( cos)a - b)  =     1  / (ca cb + sa sb)

Right side =    1  /  (  ca cb ( 1 + sa sb / ca cb))

=  1 / ( ca cb *  ( ca cb + sa sb) / ca cb)

The 'ca cb' cancels out so

Right side = 1 / (ca cb + sa sb)  = left side..

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