Answer:
C. (-3, 1)
Step-by-step explanation:
[tex] - x + y = 4 \\ \therefore \: y = x + 4...(1) \\ \& \: 3x - 4y = - 13....(2) \\ substituting \: y = x + 4 \: in \: equation \: (2) \\ 3x - 4(x + 4) = - 13 \\ 3x - 4x - 16 = - 13 \\ - x = 16 - 13 \\ - x = 3 \\ \huge \red{ \boxed{x = - 3}} \\ plug \: x = - 3 \: in \: equation \: (1) \\ y = - 3 + 4 \\ \huge \purple{ \boxed{y = 1}} \\ \\ \orange{ \boxed{ \bold {\therefore \: (x, \: \: y) = ( - 3, \: \: 1)} }}[/tex]
