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A chemist makes a solution of NaOH for use in an experiment. She dissolves 0.00500 mol NaOH in 1.00 L H2O. The NaOH completely dissociates to form a solution with [OH− ] = 0.00500 M. What is the pOH of this solution?

Respuesta :

JayDifferent

Answer:

C(2.30)

Explanation:

mickymike92

The pOH of the NaOH solution is 2.3.

What is pOH?

pOH is the negative logarithm to base ten of the hydroxide ions concentration of a solution.

  • pOH = -log[OH-]

The concentration of the NaOH solution is calculated as follows:

  • Concentration = moles/volume in L

Concentration = 0.005/1.00 = 0.005 M

Concentration of OH- in the solution = 0.005 M

pOH = -log(0.005)

pOH = 2.3

Therefore, the pOH of the solution is 2.3.

Learn more about pOH at: https://brainly.com/question/13557815