Brai9nessa8udreepo
Brai9nessa8udreepo Brai9nessa8udreepo
  • 20-07-2016
  • Mathematics
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The radius of a sphere is increasing at a constant of 2 cm/sec at the instant when the volume of the sphere is increasing at 32pi cm^3. sec, What is the surface area of the sphere?

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meerkat18
meerkat18 meerkat18
  • 20-07-2016
The formula for the volume (v) of sphere is,
                         v = 4πr³ / 3
The derivative is,
                          dv/dt = 4πr²(dr/dt)
It is given that the radius changes at a rate of 2 cm/sec which means that dr/dt is 2. dv/dt is also given to be 32π cm³/sec. Substituting these to the given,
                           32π = 4πr² x 2
The value of 4πr² which is the surface area is equal to 16π. Thus, the surface area of the sphere is 16π cm².
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