Answer:
Step-by-step explanation:
Given that the time (in hours) required to repair a machine is an exponentially distributed random variable with parameter λ=0.1.
Let X be the time taken for a repair
The conditional probability that a repair takes at least 10 hours, given that it takes more than 8 hours
= P(X≥10/x>8)
=[tex]\frac{1-F(10)}{1-F(8)}[/tex]
Parameter = 0.1
F(10) = [tex]1-e^{-1} =1-0.6321\\=0.3679[/tex]
F(8) = [tex]1-e^{-0.8} \\=0.551[/tex]
Hence answer =0.8187
