Answer:
0.079mole
Explanation:
From the question given, we obtained the following data:
T = 104°C = 104 + 273 = 377K
V = 6.8L
P = 270 mmHg
Recall: 760mmHg = 1atm
Therefore, 270 mmHg = 270/760 = 0.36atm
R = 0.082atm.L/Kmol
n =?
Using the ideal gas equation:
PV = nRT
We can easily obtain the number of mole as follow:
PV = nRT
n = PV /RT
n = 0.36 x 6.8 / 0.082 x 377
n = 0.079mole
The number of mole of the gas is 0.079mole
