Answer:
27588
Explanation:
Given,
Speed of the centrifuge = 15000 rpm
time, t = 220 s
Revolution = ?
1 min = 60 s
Speed of centrifuge = [tex]\dfrac{15000}{60}[/tex]
= 250 rps
Initial angular speed = 0 rps
[tex]\alpha = \dfrac{250-0}{220}[/tex]
[tex]\alpha = 1.14\ rev/s^2[/tex]
Now,
revolution
[tex]\theta = \omega_0 t - \dfrac{1}{2}\alpha t^2[/tex]
[tex]\theta = 0 + \dfrac{1}{2}\times 1.14\times 220^2[/tex]
[tex]\theta = 27588\ rev[/tex]
Hence, the number of turns is equal to 27588.
