Answer:
Maximum magnetic force on current carrying wire when wire is placed at 90 degree with magnetic field
Explanation:
As we know that the magnetic force on current carrying conductor is given as
[tex]\vec F = i(\vec L \times \vec B)[/tex]
here we have
[tex]F = i L Bsin\theta[/tex]
here we know that
[tex]\theta [/tex] = angle between length vector and magnetic field vector
so if we would like to have maximum magnetic force on the current carrying wire then
[tex]\theta = 90 [/tex]
so we have
[tex]F_{mex} = iLB[/tex]
