Answer:
Critical points: none
Step-by-step explanation:
We are given the function;
f(x)=x³+27x+4
We are required to determine the critical points
First we can find the derivative of the function;
[tex]f(x)=x^3+27x+4[/tex]
Thus, the derivative will be;
[tex]f'(x)=3x^2+27[/tex]
But, at critical point the derivative is equal to zero or undefined
Therefore;
[tex]3x^2+27=0\\3x^2=-27\\x^2=-9\\[/tex]
Thus, the function has no critical points
