Answer:it has no solutions
Step-by-step explanation:
The given system of equations is expressed as
2y = 2x + 4 - - - - - - - - - - 1
y = 3x + 2 - - - - - - - - - - - - 2
We would apply the substitution method by substituting equation 1 into equation 2. It becomes
2(3x + 2) = 2x + 4
6x + 4 = 2x + 4
Subtracting 2x and 4 from the left hand side and the right hand side of the equation, it becomes
6x - 2x + 4 - 4 = 2x - 2x + 4 - 4
4x = 0
Therefore, the system of equations have no solutions.
