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An elevator accelerates upward at 2.0 m/s?,
as illustrated in the diagram below:
The passenger has a mass of 85 kg.
Calculate the force the floor exerts on the
passenger.

Respuesta :

Answer:

Force the floor exerts on the  passenger is 833 N.

Explanation:

  • Weight of passenger ([tex]F_{g}[/tex]) = mg = 85 × 9.8 N = 833 N
  • Force the floor exerts on the  passenger ([tex]F_{N}[/tex]) = ?
  • For the elevator with the speed as 2.0 m/s the net force is zero, it means that the force is balanced.

                                       i.e. [tex]F_{N}[/tex] = - [tex]F_{g}[/tex] = -mg = 833 N

                                       hence  [tex]F_{N}[/tex] is 833 N

  • If the lift was not at a constant speed i.e. if it had acceleration ([tex]m/s^{2}[/tex])  then the case would be different.

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