Answer:
120
Step-by-step explanation:
No of math books = 4
No of History books = 7
Since no two math books are next to each other, we can say each math book is sandwiched between two history books like
H⇔M⇔H
We can assume that this there books in system above is binded together, thus we will have
3 binded combinations H⇔M⇔H
1 single Math book M
1 single History book H
No of possible arrangements = (3+1+1)! =5! = 5 x 4 x 3 x 2 x 1 = 120
