ohnoitsstephanie206 ohnoitsstephanie206
  • 20-02-2020
  • Mathematics
contestada

Which of the following equations has no real solutions? A. 4x − 6 = 24x − 6 B. 4(x + 6) = 4(x + 15) C. 4x − 6 = 4x − 6 D. 4(x − 6) = 4x − 24

Respuesta :

jikanTime
jikanTime jikanTime
  • 20-02-2020

Answer:

B. 4(x + 6) = 4(x + 15)

Step-by-step explanation:

  • solve parentheses: 4x + 24 = 4x + 60

  • subtract or add like terms:

4x + 24 = 4x + 60

- 4x - 4x

  • 24 < 60, they are not equal nor do they have x or y intercepts, therefore this equation has no real solution.
Answer Link
ghanami
ghanami ghanami
  • 20-02-2020

Answer:

B. 4(x + 6) = 4(x + 15)

Step-by-step explanation:

hello :

4(x + 6) = 4(x + 15)

means :  4x+24 = 4x+60

                  24 = 60 .....right

Answer Link

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