A) g(36) = 1260
B) f(2) + 1 = 9
Solution:
Given that,
[tex]f(x) = 3x + 2\\\\g(x) = x^2-x[/tex]
Find each value
A) g(36)
Substitute x = 36 in g(x)
[tex]g(36) = (36)^2 - 36\\\\g(36) = 1296-36\\\\g(36) = 1260[/tex]
B) f(2) + 1
Substitute x = 2 in f(x)
[tex]f(2) + 1 = 3(2) + 2 + 1\\\\f(2) + 1 = 6 + 2 + 1\\\\f(2) + 1 = 9[/tex]
Thus the values are found
