Answer:
B) y − 3 = -e (x + 1)
Step-by-step explanation:
Use second fundamental theorem of calculus.
y = 3 − ∫₋₁ˣ e^(-t³) dt
dy/dx = -e^(-x³) (1)
At x = -1:
y = 3
dy/dx = -e
Using point-slope form, the equation of the tangent line is:
y − 3 = -e (x + 1)
