Answer:
[tex]\frac{1}{3}(3.14)(4^2)(6)[/tex]
Step-by-step explanation:
The volume of a cylinder is given by:
[tex]\pi r^2 h[/tex]
Where [tex]r=4 ft[/tex] is the radius of the cylinder and [tex]h=6 ft[/tex] is the height of the cylinder.
Therefore the volume of this cylinder becomes: [tex]3.14(4^2)(6)[/tex]
The volume of a cone that fits directly into this cylinder is one-third of the the volume of this cylinder.
The required volume is [tex]\frac{1}{3}(3.14)(4^2)(6)[/tex]
