Answer:
Therefore the correct option is third
i.e determinant A i.e |A| = 30
Step-by-step explanation:
Given:
[tex]A=\left[\begin{array}{ccc}-2&2&b\\0&3&a\\0&0&-5\end{array}\right][/tex]
To Find:
determinant A i.e |A| = ?
Solution:
Determinant A is given as
[tex]|A|=-2(3\times -5-0\times a)-2(0\times -5-0\times a)+b(0\times 0-0\times 3)\\\\|A|=-2(-15)-2(0)+b(0)\\\\|A|=30[/tex]
Therefore the correct option is third one i.e determinant A i.e |A| = 30
