Answer:
[tex]z_{{\frac{\alpha}{2}}}=z_{0.035}=1.81[/tex]
Step-by-step explanation:
We are asked to compute [tex]z_{{\frac{\alpha}{2}}[/tex] that corresponds to confidence level of 93%.
[tex]93\%=\frac{93}{100}=0.93[/tex]
[tex]\alpha=1-0.93=0.07[/tex]
[tex]\frac{\alpha}{2}=\frac{0.07}{2}[/tex]
[tex]\frac{\alpha}{2}=0.035[/tex]
Now, we will use normal distribution table to find the z-score that corresponds to area of 0.035.
[tex]z_{0.035}=-1.81[/tex]
Therefore, the value of [tex]z_{{\frac{\alpha}{2}}[/tex] is [tex]1.81[/tex].
