Respuesta :

frika

Answer:

[tex]f(x)+3=2x^2-3x+7[/tex]

Step-by-step explanation:

Given

[tex]f(x)=2x^2-3x+4[/tex]

To find [tex]f(x)+3,[/tex] simply add 3 to the function expression in the left side:

[tex]f(x)+3\\ \\=2x^2-3x+4+3\\ \\=2x^2-3x+7[/tex]

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