hh4ondChapmaexperon
hh4ondChapmaexperon hh4ondChapmaexperon
  • 17-06-2016
  • Biology
contestada

A tow truck exerts a net horizontal force of 1050 n on a 760-kg car. what is the acceleration of the car during this time?

Respuesta :

Ricky2000
Ricky2000 Ricky2000
  • 17-06-2016
a = f/m

a= 1050/760

a= 1.38m/s^2
Answer Link
IlaMends IlaMends
  • 09-01-2019

Answer: The acceleration of the car during this time is 1.38 [tex]m/s^2[/tex].

Explanation:

Force exerted on the two truck = 1050 N

Mass of the car = 760 kg

According to Newton's second law of Motion;

[tex]Force=Mass \times Acceleration[/tex]

[tex]1050 N=760 kg\times Acceleration[/tex]

[tex]Acceleration=\frac{1050 N}{760 kg}=1.38 m/s^2[/tex]

The acceleration of the car during this time is 1.38 [tex]m/s^2[/tex].

Answer Link

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