Answer:
The value of x can be 5 or 2
Step-by-step explanation:
In given triangle ABC
Interior Angle A = [tex]x^{2} +3x+20[/tex]
Interior Angle B = [tex]x^{2} +14x-5[/tex]
Exterior Angle I = [tex]3x^{2} +10x+25[/tex]
We know that
Exterior Angle of triangle is summation of corresponding opposite angles
Angle I = Angle A + Angle B
[tex]3x^{2} +10x+25= (x^{2} +3x+20)+(x^{2} +14x-5)[/tex]
[tex]3x^{2} +10x+25= 2x^{2} +17x+15[/tex]
[tex]1x^{2}-7x+10=0[/tex]
[tex]x^{2}-2x-5x+10=0[/tex]
[tex]x(x-2)-5(x-2)=0[/tex]
[tex](x-5)(x-2)=0[/tex]
