Answer:
[tex] 2x\sqrt{10}-2x\sqrt 5[/tex]
Step-by-step explanation:
[tex]\sqrt{5x} (\sqrt{8x^2}-2\sqrt{x})\\
\mathrm{Multiply \: parentheses \: by \sqrt{5x}}\\
=\sqrt{5x \times 8x^2}-2\sqrt{5x \times x}\\
=x\sqrt {4\times 10 x}-2x\sqrt{5}\\
=2x\sqrt{10}-2x\sqrt{5}[/tex]
