alex44492 alex44492

20-10-2019
Chemistry

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If 100.0J are added to 20g of water at 30.0c what will be the final temperature

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adebowalebabajide91 adebowalebabajide91

20-10-2019

Answer:

31.19

Explanation:

H= MC x Temperature change

100 = (20/1000) x 4200 x A

100= 84A

A= 1.19

A=X-30

1.19=X-30

X=30+1.19

X=31.19

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