Answer:
The correct answer is - AABb/AaBb : aaBB/Aabb would be 1:1.
Explanation:
The cross between AaBb and AAbb will produce AB, Ab, aB, aB and Ab, Ab, Ab, Ab gametes respectively. These gametes from zygote and produce the two phenotypic character one with AABb/AaBb and aaBB/Aabb. The first phenotype would have both dominant traits while in others have only A dominant and B recessive in the phenotype of offspring.
Thus, the correct answer is - AABb/AaBb : aaBB/Aabb would be 1:1.
