brookiebear17
brookiebear17
19-05-2016
Mathematics
contestada
How do you solve this?
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SapphieFallenAngel
SapphieFallenAngel
19-05-2016
you X to the second power.. 4 to the second power is 16 and 16-16=0 so x=4
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penfila11Pen
penfila11Pen
19-05-2016
Add 16
x² - 16 = 0
+ 16 +16
x² = 16
Take square root
[tex] \sqrt{x^2} = \sqrt{16} [/tex]
Remember when you take the square root of a perfect square you get two values. +ve and -ve
x = -4
x = 4
because (-4)² = 16
( 4)² = 16
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