Answer:
The approximate positive value of x is 0.92.
Step-by-step explanation:
Given,
[tex](x+5)^2 = 35[/tex]
[tex]x+5 = \pm \sqrt{35}[/tex]
[tex]x = \pm \sqrt{35}-5[/tex]
Thus,
[tex]x = \sqrt{35}-5[/tex] or [tex]x=-\sqrt{35}-5[/tex]
By taking positive value,
[tex]x = \sqrt{35}-5[/tex]
[tex]x=5.91607978 - 5 = 0.91607978\approx 0.92[/tex]
⇒ First option is correct.
