Respuesta :

prech

change the mg in the question to g which is

[tex] {10}^{ - 3?} [/tex]

if 10cc contains 5g therefore

[tex] {10}^{ - 3?} \times 350 = 0.35[/tex]

0.35g would give?

[tex]10 \times 0.35 \div 5 = 0.7cc \: of \: volume[/tex]

Otras preguntas