Seudónimo Seudónimo
  • 19-09-2019
  • Mathematics
contestada

Rationalize the denominator.
sqrt(3)/(fourth root of 2)

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Аноним Аноним
  • 19-09-2019

Start with

[tex]\dfrac{\sqrt{3}}{\sqrt[4]{2}}[/tex]

Multiply and divide by the cubic root of two:

[tex]\dfrac{\sqrt{3}}{\sqrt[4]{2}}\cdot\dfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}[/tex]

Multiplying the fractions leads to

[tex]\dfrac{\sqrt{3}}{\sqrt[4]{2}}\cdot\dfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}=\dfrac{\sqrt{3}\sqrt[4]{2}}{\sqrt[4]{2\cdot 2^3}}=\dfrac{\sqrt{3}\sqrt[4]{2}}{\sqrt[4]{2^4}}=\dfrac{\sqrt{3}\sqrt[4]{2}}{2}[/tex]

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