zrobinson623 zrobinson623
  • 18-09-2019
  • Physics
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14. A 7 Kg box sits on an incline of 30°, what is the force down the incline?​

Respuesta :

danielagustinmacri
danielagustinmacri danielagustinmacri
  • 19-09-2019

Answer:

Explanation:

To know the force down you need to divide the force into two components X parallel with the inclined surface and Y, the perpendicular one.

F= m* g= 7kg*9,8m/s^2= 68.6 N

Fy= F*cos(30) = - N

Fx= F*sen(30)

N = normal. Force which is perpendicular to the movement equal and opposite to weigh in the plane.

Friction force = Fr= Coef *N

In the inclined there're Fx to one side and Fr to the other side. Perpendicular to it there are Fy and N

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