Answer:
Magnetic force, [tex]F=1.22\times 10^{-7}\ N[/tex]
Explanation:
It is given that,
Charge, [tex]q=3.4\ nC=3.4\times 10^{-9}\ C[/tex]
Velocity, v = 4.7 m/s
Magnetic field, [tex]B=-1.4i+7.52j[/tex]
[tex]|B|=\sqrt{(-1.4)^2+(7.52)^2}=7.64\ T[/tex]
Magnetic force is given by :
[tex]F=q\times v\times B[/tex]
[tex]F=3.4\times 10^{-9}\ C\times 4.7\ m/s\times 7.64\ T[/tex]
[tex]F=1.22\times 10^{-7}\ N[/tex]
So, the magnetic force on this particle is [tex]1.22\times 10^{-7}\ N[/tex]. Hence, this is the required solution.
