Answer: Option A
[tex]P(A|B)=\frac{3}{5}=0.6[/tex]
Step-by-step explanation:
By Definition the probability of A given B is:
[tex]P(A|B)=\frac{P(A\ and\ B)}{P(B)}=\frac{A\ and\ B}{B}[/tex]
Note that the number of students playing basketball is 6
The number of students playing soccer is 5
The number of students who play both sports is 3
Therefore we have that:
[tex]P(A|B)=\frac{3}{5}=0.6[/tex]
The answer is the option A
