ethanlperry
ethanlperry ethanlperry
  • 17-07-2019
  • Mathematics
contestada

Simplify each expression. e^(ln 1) = e^(ln 5x) =

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jdoe0001 jdoe0001
  • 17-07-2019

[tex]\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ e^{\ln(1)}=e^{\ln(5x)}\implies e^{\log_e(1)}=e^{\log_e(5x)}\implies 1=5x\implies \cfrac{1}{5}=x[/tex]

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zainabashfaq66 zainabashfaq66
  • 22-07-2020

Answer: it’s 1 and 5x on edg

Step-by-step explanation:

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