siddsrrm siddsrrm
  • 20-05-2019
  • Mathematics
contestada

Given: △EIJ, k(O, r)
EI = EJ = r=10 cm
EP ⊥ IJ
Find: JP

Given EIJ kO r EI EJ r10 cm EP IJ Find JP class=

Respuesta :

frika
frika frika
  • 29-05-2019

Answer:

[tex]JP=5\sqrt{3}\ cm[/tex]

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

[tex]h=\dfrac{a\sqrt{3}}{2},[/tex]

where a is the side length.

So,

[tex]h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.[/tex]

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