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20-05-2019
Mathematics

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8) Factor each sum or difference of cubes completely.
a. 8x3 + 27

Respuesta :

20-05-2019

Answer:

[tex]\large\boxed{(2x+3)(4x^2-6x+9)}[/tex]

Step-by-step explanation:

[tex]8=2^3\\\\8x^3=2^3x^3=(2x)^3\\\\27=3^3\\\\8x^3+27=(2x)^3+3^3\qquad\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+3)\bigg((2x)^2-(2x)(3)+3^2\bigg)=(2x+3)(4x^2-6x+9)[/tex]

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