Write x^2 + 6x -7 in the form (x+a)^2 +b where a and b are integers please
Answer:
[tex](x + 3) {}^{2} - 16[/tex]
Step-by-step explanation:
[tex] {x}^{2} + 6x - 7 = (x + 3) {}^{2} - (3) {}^{2} - 7 \\ = (x + 3) {}^{2} - 16[/tex]