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  • 17-05-2019
  • Mathematics
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4x+2y=0 3x-y=-10 solve the system

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Аноним Аноним
  • 17-05-2019

Divide the first equation by 2:

[tex]\begin{cases}2x+y=0\\3x-y=-10\end{cases}[/tex]

Sum the two equations:

[tex]5x = -10[/tex]

Divide both sides by 5:

[tex]x=-2[/tex]

Substitute this value for x in one of the equation (for example the first) and solve for y:

[tex]-8+2y = 0 \iff 2y=8 \iff y=4[/tex]

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