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This problem is worth 20 points! Please Help ASAP!!!!!!! You don't need to show work!
Pamela has a box that contains six books of fiction, seven books of humor, five books of plays, and two books of adventure. She removes one book from the box at random. Then places the book back in the box and randomly removes another book. What is the probability that Pamela first removes a book of humor followed by a book of plays?


A. 3/5



B. 1/8



C. 7/26



D. 7/80

Respuesta :

lucic

Answer:

D.7/80

Step-by-step explanation:

⇒The question is on probability with replacement

⇒The events taken in this probability are independent of each other

⇒Formulae for combined probability of these events is the product of the probabilities of the event

Given;

6 books for fiction, F=6

7 books for humor, H=7

5 books for play, P=5

2 books for adventure, A=2

Evaluating

n(S)=6+7+5+2=20

P(H)=7/20

P(P)=5/20

P(H ∩ P)=P(H)×P(P)

7/20 × 5/20 =7/80

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