Answer:
[tex]\large\boxed{16x^2-24x+9=(4x-3)^2}[/tex]
Step-by-step explanation:
[tex]\text{Perfect square:}\ (a-b)^2=a^2-2ab+b^2\\=======================\\\\25x^2-20x-16\to\text{NOT. Because is}\ -16=-4^2\\\\9a^2-30a-25\to\text{NOT. Because is}\ -25=-5^2\\\\25b^2-15b+9=(5b)^2-2(5b)\left(\dfrac{3}{2}\right)+3^2\to\text{NOT. Because is}\ b=\dfrac{3}{2}\ \text{and}\ b^2=3^2\\\\16x^2-24x+9=(4x)^2-2(4x)(3)+3^2=(4x-3)^2\ \boxed{YES\ :)}[/tex]
