Respuesta :

jg71

[tex] {x}^{2} = 12 \\ x = \sqrt{12} \\ x = \sqrt{4} \times \sqrt{3} \\ x = 2 \times \sqrt{3} \\ x = 2 \sqrt{3} [/tex]

Gyzmo

Answer:

x=±[tex]2\sqrt{3}[/tex]

Step-by-step explanation:

x²=12

Take square root of both sides.

x=±[tex]\sqrt{12}[/tex]

It is ±[tex]\sqrt{12}[/tex] because [tex](-\sqrt{12})^{2} =12[/tex].

Simplify.

x=±[tex]2\sqrt{3}[/tex]

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