ria2389
ria2389 ria2389
  • 16-04-2019
  • Mathematics
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Is this correct??????

Is this correct class=

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tramserran
tramserran tramserran
  • 16-04-2019

Answer:   [tex]\bold{c)\quad \sqrt[3]{15} }[/tex]

Step-by-step explanation:

[tex]\large\sqrt[3]{-3} \cdot \large\sqrt[3]{-5} =\large\sqrt[3]{(-3)(-5)} =\large\boxed{\sqrt[3]{15}}[/tex]

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