Answer:
[tex](x+8)^{2} +(y+3)^{2}=4[/tex]
Step-by-step explanation:
we know that
The equation of the circle in center radius form is equal to
[tex](x-h)^{2} +(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the center of the circle
r is the radius
In this problem we have
[tex](h,k)=(-8,-3)[/tex]
[tex]r=2\ units[/tex]
substitute
[tex](x+8)^{2} +(y+3)^{2}=2^{2}[/tex]
[tex](x+8)^{2} +(y+3)^{2}=4[/tex]
