Respuesta :

Willchemistry
Molar mass FeCl₂ = 126.751 g/mol

450 mL / 1000 = 0.45 L

1 mole ------- 126.751 g
? mole ------- 200 g

moles = 200 * 1 / 126.751

moles = 200 / 126.751

= 1.57789 moles FeCl₂

M = n / V

M = 1.57789 / 0.45

= 3.50 Mol/L or M

hope this helps!

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