Yeah sure absolutely.
So the volume of a cone can be calculated with [tex]V= \pi r^{2} \frac{h}{3}[/tex], you can substitute values into this like the following [tex]V = 3.14[/tex] × [tex] 12^{2} [/tex] × [tex] \frac{8}{3} [/tex], which is equal to [tex]1205 cm^{3} [/tex]
