Answer:
The dimension of the frame are [tex](10\ in)by(12\ in)[/tex]
Step-by-step explanation:
Let
x-----> the width of the frame
we know that
[tex](2x+8)(2x+10)=120[/tex] ----> equation that represent the situation
[tex](2x+8)(2x+10)=120\\ \\4x^{2}+20x+16x+80=120\\ \\4x^{2}+36x-40=0[/tex]
Using a graphing tool to solve the quadratic equation
The solution is [tex]x=1\ in[/tex]
see the attached figure
therefore
The dimension of the frame are
[tex](2(1)+8)*(2(1)+10)[/tex]
[tex](10\ in)*(12\ in)[/tex]
