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Suppose the house in question 3 is located in cleveland where the annual average solar flux is 160 w/m2 . if 10 m2 of solar panels operating at 20 percent efficiency were installed on this house to collect and store solar energy in the form of hot water:

Respuesta :

Solar flux that incident on it is given as

S = 160 W/m/m

Now we know that the area of solar panels is given as

A = 10 m^2

So total solar power received by solar panels is given as

[tex]Power Received = (Solar flux) \times (Area)[/tex]

[tex]P = S\times A[/tex]

now here we have

[tex]P = 160 \times 10 [/tex]

[tex]P = 1600 W[/tex]

now we know that efficiency of the solar panels is 20%

so total output power will be

[tex]efficiency = \frac{P_{out}}{P_{in}}[/tex]

[tex]0.20 = \frac{P_{out}}{1600}[/tex]

[tex]P_{out} = 320 W[/tex]

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