jasminesilva16
jasminesilva16 jasminesilva16
  • 17-02-2019
  • Mathematics
contestada

Given: sin = 4/5 and cos x = -5/13 ; evaluate the following expression. Cos 2x

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Аноним Аноним
  • 17-02-2019

For every possible angle [tex]x [/tex], the fundamental law of trigonometric states that

[tex] \sin^2(x)+\cos^2(x) = 1 [/tex]

In your case, the inputs you provided would lead to

[tex] \dfrac{16}{25}+\dfrac{25}{169} = \dfrac{3329}{4225} \approx 0.8 \neq 1 [/tex]

So, it is not possible that, for a certain angle x, we have

[tex]\sin(x) = \dfrac{4}{5},\quad \cos(x) = -\dfrac{5}{13} [/tex]

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