mknkepro5ow8kl4 mknkepro5ow8kl4
  • 21-01-2019
  • Physics
contestada

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height of the image

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carlosego
carlosego carlosego
  • 22-01-2019

To solve this problem we use an amplification formula for divergent lenses

[tex]M = \frac{i}{o} = \frac{h'}{h}[/tex]

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

[tex]M = \frac{4mm}{12mm} = \frac{h'}{18mm}[/tex]

[tex]h'= 18mm\frac{4mm}{12mm}[/tex]

h '= 6 mm

The height is 6 mm

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