vinavel vinavel
  • 18-12-2018
  • Physics
contestada

the force needed to lift a 3000 N truck using a jack with a MA of 15

Respuesta :

aristocles aristocles
  • 27-12-2018

As we know that mechanical advantage is defined as

[tex]MA = \frac{F_o}{F_{in}}[/tex]

now here we have

[tex]MA = 15[/tex]

also we have

[tex]F_O = 3000 N[/tex]

now we will have

[tex]15 = \frac{3000}{F_{in}}[/tex]

now we will have

[tex]F_{in} = \frac{3000}{15}[/tex]

[tex]F_{in} = 200 N[/tex]

so our applied force will be 200 N

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