[tex]\bf \stackrel{\textit{solving for \underline{y}}}{3y+12=2x}\implies 3y=2x-12\implies y=\cfrac{2x-12}{3}\implies y=\cfrac{2x}{3}-\cfrac{12}{3} \\\\\\ y=\cfrac{2}{3}x-4\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
